Mock Exam 1
VCE Biology Units 3 & 4 | DNA Structure, Gene Expression, Protein Synthesis and Regulation
✎ 120 marks total • approximately 150 minutes. Complete ALL questions on paper before opening the Model Answers lesson. Reading time: 15 minutes (recommended). No notes.
SECTION A — MULTIPLE CHOICE (40 marks)
Question 1 (1 mark)
Which three components make up a single DNA nucleotide?
✎ Circle your answer
A) Deoxyribose sugar, phosphate group, nitrogenous base
B) Ribose sugar, phosphate group, amino acid
C) Deoxyribose sugar, phosphate group, fatty acid
D) Nitrogenous base, ribose sugar, peptide bond
Question 2 (1 mark)
In DNA, adenine forms hydrogen bonds with which base, and how many hydrogen bonds are formed?
✎ Circle your answer
A) Guanine, 3 bonds
B) Thymine, 2 bonds
C) Cytosine, 3 bonds
D) Uracil, 2 bonds
Question 3 (1 mark)
Chargaff’s rules state that in double-stranded DNA:
✎ Circle your answer
A) %A = %G and %T = %C
B) %A = %T and %G = %C
C) %A = %C and %G = %T
D) All four bases are present in equal amounts
Question 4 (1 mark)
The two strands of a DNA double helix are described as ‘antiparallel’ because:
✎ Circle your answer
A) They are held together by ionic bonds
B) One strand runs 5’→3′ while the other runs 3’→5′
C) They twist in opposite directions around separate axes
D) They contain different sugars
Question 5 (1 mark)
The Meselson-Stahl experiment, using density-labelled nitrogen isotopes (15N/14N), provided evidence that DNA replication is:
✎ Circle your answer
A) Conservative
B) Dispersive
C) Semi-conservative
D) Semi-dispersive
Question 6 (1 mark)
Which enzyme unwinds the DNA double helix at the replication fork by breaking hydrogen bonds between base pairs?
✎ Circle your answer
A) DNA ligase
B) Helicase
C) Primase
D) Topoisomerase
Question 7 (1 mark)
Single-strand binding proteins (SSBPs) function during replication to:
✎ Circle your answer
A) Synthesise the RNA primer
B) Prevent the separated DNA strands from reannealing
C) Proofread newly synthesised DNA
D) Join Okazaki fragments
Question 8 (1 mark)
Primase is required during DNA replication because:
✎ Circle your answer
A) DNA polymerase cannot initiate synthesis without a free 3′-OH group provided by a primer
B) DNA polymerase cannot unwind the double helix
C) DNA polymerase cannot proofread without primase
D) Primase removes RNA primers
Question 9 (1 mark)
The lagging strand is synthesised discontinuously as Okazaki fragments because:
✎ Circle your answer
A) DNA polymerase can only synthesise DNA in the 5’→3′ direction
B) The lagging strand template is shorter
C) DNA polymerase moves away from the replication fork on both strands
D) Ligase cannot join a continuous strand
Question 10 (1 mark)
Which enzyme joins Okazaki fragments together by forming phosphodiester bonds between them?
✎ Circle your answer
A) DNA polymerase III
B) DNA ligase
C) Primase
D) Helicase
Question 11 (1 mark)
In prokaryotes, which enzyme removes RNA primers and replaces them with DNA nucleotides?
✎ Circle your answer
A) DNA polymerase I
B) DNA polymerase III
C) RNA polymerase
D) Reverse transcriptase
Question 12 (1 mark)
The ‘proofreading’ function of DNA polymerase relies on its:
✎ Circle your answer
A) Helicase activity
B) 3’→5′ exonuclease activity, which removes mismatched nucleotides
C) Ligase activity
D) 5’→3′ exonuclease activity only
Question 13 (1 mark)
Mismatch repair differs from proofreading in that mismatch repair:
✎ Circle your answer
A) Occurs during synthesis, immediately correcting the error as it is made
B) Occurs after replication is complete, scanning the newly synthesised strand for errors missed by proofreading
C) Only removes RNA primers
D) Is performed exclusively by helicase
Question 14 (1 mark)
Nucleotide excision repair (NER) is primarily responsible for removing:
✎ Circle your answer
A) Single mismatched bases
B) Bulky helix-distorting lesions such as UV-induced thymine dimers
C) Whole chromosome segments
D) RNA primers
Question 15 (1 mark)
A person with xeroderma pigmentosum has a defect in which repair pathway, resulting in extreme sensitivity to UV light and a high skin cancer risk?
✎ Circle your answer
A) Mismatch repair
B) Nucleotide excision repair
C) Base excision repair only, for oxidative damage
D) Homologous recombination
Question 16 (1 mark)
Telomeres protect chromosomes primarily by:
✎ Circle your answer
A) Coding for proteins essential to replication
B) Providing a buffer of repetitive non-coding sequence at chromosome ends that is progressively shortened, protecting coding DNA from loss
C) Binding histones only
D) Preventing mutation of the centromere
Question 17 (1 mark)
Telomerase is an enzyme that:
✎ Circle your answer
A) Is active in most differentiated somatic cells to prevent ageing
B) Adds repetitive telomeric sequence to chromosome ends using an internal RNA template, and is typically active in germline, stem and cancer cells
C) Removes telomeric sequence to signal cell death
D) Joins Okazaki fragments on the leading strand
Question 18 (1 mark)
The ‘end-replication problem’ refers to the fact that:
✎ Circle your answer
A) DNA polymerase cannot fully replicate the very end of the lagging strand template, causing progressive shortening of chromosomes each division
B) Helicase cannot unwind the final base pairs
C) Ligase cannot seal the final Okazaki fragment
D) Telomerase always fully compensates for shortening in somatic cells
Question 19 (1 mark)
A point mutation that changes a codon but still codes for the same amino acid is called a:
✎ Circle your answer
A) Missense mutation
B) Nonsense mutation
C) Silent mutation
D) Frameshift mutation
Question 20 (1 mark)
A point mutation that changes a codon to code for a different amino acid is called a:
✎ Circle your answer
A) Silent mutation
B) Missense mutation
C) Nonsense mutation
D) Duplication
Question 21 (1 mark)
A point mutation that converts a codon into a premature stop codon is called a:
✎ Circle your answer
A) Missense mutation
B) Silent mutation
C) Nonsense mutation
D) Inversion
Question 22 (1 mark)
Which chromosomal mutation involves a segment of a chromosome breaking off, flipping, and reattaching in the reverse orientation?
✎ Circle your answer
A) Deletion
B) Duplication
C) Inversion
D) Translocation
Question 23 (1 mark)
A chromosomal mutation in which a segment of one chromosome becomes attached to a non-homologous chromosome is called a:
✎ Circle your answer
A) Inversion
B) Translocation
C) Duplication
D) Deletion
Question 24 (1 mark)
Nondisjunction during meiosis, resulting in gametes with an abnormal chromosome number (e.g. trisomy 21), refers to:
✎ Circle your answer
A) Failure of homologous chromosomes or sister chromatids to separate correctly
B) A point mutation in a single gene
C) Failure of DNA polymerase to proofread
D) A frameshift mutation
Question 25 (1 mark)
Why is the genetic code described as ‘degenerate’?
✎ Circle your answer
A) Because it mutates rapidly
B) Because most amino acids are specified by more than one codon
C) Because it only applies to prokaryotes
D) Because some codons code for no amino acid
Question 26 (1 mark)
The genetic code is described as (near) ‘universal’ because:
✎ Circle your answer
A) Every organism has an identical genome
B) The same codons specify the same amino acids in almost all organisms, with only minor exceptions (e.g. in some mitochondrial genomes)
C) All organisms produce the same proteins
D) Only humans and bacteria share the code
Question 27 (1 mark)
The ‘wobble hypothesis’ explains why:
✎ Circle your answer
A) Ribosomes can shift reading frame during translation
B) A single tRNA can pair with more than one codon due to flexible pairing at the third codon position
C) DNA polymerase makes errors during replication
D) mRNA can be translated in either direction
Question 28 (1 mark)
Which codon signals both the start of translation and codes for the amino acid methionine?
✎ Circle your answer
A) UAA
B) AUG
C) UGA
D) GUG
Question 29 (1 mark)
Which of the following is NOT a stop codon?
✎ Circle your answer
A) UAA
B) UAG
C) UGA
D) UGG
Question 30 (1 mark)
A ribosome is composed of:
✎ Circle your answer
A) DNA and protein
B) Ribosomal RNA (rRNA) and protein, forming large and small subunits
C) mRNA and tRNA only
D) Lipid and protein
Question 31 (1 mark)
Free ribosomes in the cytosol typically synthesise proteins that:
✎ Circle your answer
A) Are secreted from the cell or inserted into membranes
B) Function within the cytosol or nucleus of that same cell
C) Are always non-functional
D) Cannot be modified after translation
Question 32 (1 mark)
Which of the following is a post-translational modification of a protein?
✎ Circle your answer
A) Splicing of introns from pre-mRNA
B) Addition of a 5′ cap to mRNA
C) Phosphorylation of the folded protein by a kinase
D) Addition of a poly-A tail to mRNA
Question 33 (1 mark)
An operon is best described as:
✎ Circle your answer
A) A single eukaryotic gene with multiple exons
B) A cluster of prokaryotic structural genes transcribed together from one promoter, producing a single polycistronic mRNA
C) A eukaryotic enhancer sequence
D) A type of transcription factor
Question 34 (1 mark)
The lac operon is described as ‘inducible’ because:
✎ Circle your answer
A) It is transcribed constantly regardless of conditions
B) Transcription is switched on in the presence of an inducer (allolactose), which removes the repressor from the operator
C) Transcription is switched off in the presence of tryptophan
D) It only functions in eukaryotic cells
Question 35 (1 mark)
The trp operon is described as ‘repressible’ because:
✎ Circle your answer
A) The structural genes are transcribed only when tryptophan (acting as a co-repressor) binds the repressor protein, allowing it to bind the operator and block transcription
B) It requires an inducer to switch on transcription
C) It has no operator sequence
D) It is only found in eukaryotes
Question 36 (1 mark)
Which molecule acts as a co-repressor in the trp operon system, switching off transcription of tryptophan-synthesising genes when it is abundant?
✎ Circle your answer
A) Allolactose
B) Tryptophan
C) cAMP
D) Glucose
Question 37 (1 mark)
DNA methylation, an epigenetic modification, typically involves:
✎ Circle your answer
A) Addition of a methyl group to cytosine bases (often at CpG sites), generally associated with reduced transcription
B) Addition of a phosphate group to DNA, increasing transcription
C) Removal of histones from DNA
D) Addition of an amino acid to DNA
Question 38 (1 mark)
Histone acetylation tends to:
✎ Circle your answer
A) Condense chromatin and silence gene expression
B) Loosen chromatin structure, making DNA more accessible and increasing transcription
C) Cause frameshift mutations
D) Have no effect on gene expression
Question 39 (1 mark)
X-chromosome inactivation in female mammals, which forms a condensed Barr body, is an example of epigenetic regulation because it:
✎ Circle your answer
A) Changes the DNA sequence of one X chromosome
B) Silences one X chromosome (randomly chosen in each cell) without altering the underlying DNA sequence, achieving dosage compensation
C) Only occurs in males
D) Deletes one copy of the X chromosome
Question 40 (1 mark)
Genomic imprinting refers to a phenomenon where:
✎ Circle your answer
A) Both parental alleles of a gene are always expressed equally
B) Expression of a gene depends on epigenetic marks acquired during gametogenesis, so only the maternal or paternal allele is expressed
C) Genes are permanently deleted from the genome
D) All genes are equally imprinted
SECTION B — EXTENDED RESPONSE (80 marks)
Question 41 (4 marks)
Describe the process of transcription in eukaryotes, including initiation, elongation and termination.
✎ Write your answer on paper
Question 42 (4 marks)
Explain how the lac operon in E. coli is regulated when lactose is absent and when lactose is present.
✎ Write your answer on paper
Question 43 (4 marks)
A segment of DNA template strand has the sequence: 3′-TACGAACTTGCA-5′. Write the mRNA sequence and the amino acid sequence encoded.
✎ Write your answer on paper
Question 44 (4 marks)
Explain why a frameshift mutation is generally more damaging than a point substitution mutation.
✎ Write your answer on paper
Question 45 (4 marks)
Describe two ways in which gene expression can be regulated at the transcriptional level in eukaryotes.
✎ Write your answer on paper
Question 46 (4 marks)
What is alternative splicing and why is it significant for proteome diversity?
✎ Write your answer on paper
Question 47 (4 marks)
Describe how siRNA (small interfering RNA) can silence gene expression. Include the role of the RISC complex.
✎ Write your answer on paper
Question 48 (4 marks)
Explain what is meant by ‘gene expression’ being regulated at multiple levels. Give one example at each of three different levels.
✎ Write your answer on paper
Question 49 (5 marks)
<strong>Extended Response 1: Protein Synthesis (a)</strong><br>Describe the process of translation, including initiation, elongation and termination.
✎ Write your answer on paper
Question 50 (3 marks)
<strong>Extended Response 1: Protein Synthesis (b)</strong><br>Explain the roles of the A, P, and E sites of the ribosome during translation.
✎ Write your answer on paper
Question 51 (4 marks)
<strong>Extended Response 2: Genetic Technologies (a)</strong><br>Describe how polymerase chain reaction (PCR) works. Include the steps in one cycle and explain the role of Taq polymerase.
✎ Write your answer on paper
Question 52 (3 marks)
<strong>Extended Response 2: Genetic Technologies (b)</strong><br>Explain one ethical consideration associated with the use of genetic technologies in medicine or agriculture.
✎ Write your answer on paper
Extended Response 3: DNA Replication Fidelity and Repair
Question 53 (3 marks)
Extended Response 3: DNA Replication Fidelity and Repair (a)Table 1 shows mutation rates measured in wild-type E. coli and in a mutant strain lacking a functional mutS gene (which encodes a key mismatch repair protein).
Strain | Mutation rate (mutations per 10^8 cell divisions)
Wild-type (mutS+) | 3
mutS-deficient (mutS-) | 450
Calculate the fold-increase in mutation rate of the mutS-deficient strain compared to the wild-type strain, showing your working.
✎ Write your answer on paper
Extended Response 3: DNA Replication Fidelity and Repair
Question 54 (4 marks)
Extended Response 3: DNA Replication Fidelity and Repair (b)
Explain the normal role of mismatch repair (MMR) proteins, such as MutS and MutL homologues, in maintaining the fidelity of the genome during and after DNA replication.
✎ Write your answer on paper
Extended Response 3: DNA Replication Fidelity and Repair
Question 55 (5 marks)
Extended Response 3: DNA Replication Fidelity and Repair (c)
The human homologue of mutS is called MSH2. Inherited (germline) mutations in MSH2 (or related MMR genes such as MLH1) cause Lynch syndrome, a hereditary condition that greatly increases the risk of colorectal and other cancers. Explain, with reference to the function of MSH2, how inheriting one defective MSH2 allele increases an individual’s cancer risk over their lifetime.
✎ Write your answer on paper
Extended Response 3: DNA Replication Fidelity and Repair
Question 56 (4 marks)
Extended Response 3: DNA Replication Fidelity and Repair (d)
Predict and justify what would happen to the frequency of small insertion/deletion (frameshift) mutations in a bacterial strain that is deficient in both mismatch repair and nucleotide excision repair, if this strain is exposed to UV radiation, compared to a wild-type strain exposed to the same UV dose.
✎ Write your answer on paper
Extended Response 4: Epigenetic Silencing of a Tumour Suppressor Gene
Question 57 (4 marks)
Extended Response 4: Epigenetic Silencing of a Tumour Suppressor Gene (a)A study compared promoter methylation of the BRCA1 tumour suppressor gene and its mRNA expression level in normal breast tissue and in breast tumour tissue from the same patients.
Tissue type | BRCA1 promoter methylation (%) | Relative BRCA1 mRNA expression
Normal breast tissue | 5 | 1.00
Breast tumour tissue | 78 | 0.06
Describe the relationship shown in the table between BRCA1 promoter methylation level and BRCA1 mRNA expression.
✎ Write your answer on paper
Extended Response 4: Epigenetic Silencing of a Tumour Suppressor Gene
Question 58 (4 marks)
Extended Response 4: Epigenetic Silencing of a Tumour Suppressor Gene (b)
Explain the molecular mechanism by which increased DNA methylation at a gene’s promoter region leads to reduced transcription of that gene.
✎ Write your answer on paper
Extended Response 4: Epigenetic Silencing of a Tumour Suppressor Gene
Question 59 (5 marks)
Extended Response 4: Epigenetic Silencing of a Tumour Suppressor Gene (c)
Distinguish between a genetic mutation and an epigenetic change (such as promoter methylation) as mechanisms for loss of tumour suppressor gene function, with reference to reversibility and heritability through cell division.
✎ Write your answer on paper
Extended Response 4: Epigenetic Silencing of a Tumour Suppressor Gene
Question 60 (4 marks)
Extended Response 4: Epigenetic Silencing of a Tumour Suppressor Gene (d)
A drug that inhibits DNA methyltransferase (DNMT) enzymes has been proposed as a treatment to reactivate silenced tumour suppressor genes, such as BRCA1, in cancer cells. Evaluate this therapeutic approach by outlining one potential benefit and one potential limitation.
✎ Write your answer on paper
✓ Finished? Open the next lesson — Model Answers — to mark your work.