Practice Exam 1
VCE Chemistry | Atomic Structure, Periodic Table, Chemical Bonding & Naming
✎ Complete ALL questions on paper before opening the Model Answers lesson. No notes. Aim for 1 minute per mark.
SHORT ANSWER
Question 1 (4 marks)
Write the full electron configuration of iron (Fe, Z=26) and identify which subshell is incompletely filled.
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Question 2 (4 marks)
Draw the Lewis structure of SOβ and explain its shape using VSEPR theory.
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Question 3 (4 marks)
Explain why the boiling point of HF (19.5Β°C) is much higher than HCl (-85Β°C) despite HCl having higher molar mass.
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Question 4 (4 marks)
Name the following compounds: (i) FeClβ (ii) NβOβ
(iii) Ca(OH)β (iv) HNOβ
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Question 5 (4 marks)
The first ionisation energies (kJ/mol) of elements across Period 3 are: Na 496, Mg 738, Al 577, Si 786, P 1012, S 1000, Cl 1251, Ar 1521.
Explain the general trend and account for the anomaly at Al and S.
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Question 6 (4 marks)
Calculate the number of protons, neutrons, and electrons in βΈβ°Brβ».
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Question 7 (4 marks)
Classify each bond as ionic, polar covalent, or non-polar covalent and explain: (i) ClβCl (ii) NaβCl (iii) OβH (iv) CβH
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Question 8 (4 marks)
Write structural formulas and IUPAC names for the three structural isomers with molecular formula CβHβO that are alcohols.
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EXTENDED RESPONSE
Extended Response 1: Periodic Trends & Electron Configuration
Question 9 (3 marks)
Extended Response 1: Periodic Trends & Electron Configuration (a)
Explain the trend in atomic radius across Period 3 (Na to Ar) and down Group 1 (Li to Cs).
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Extended Response 1: Periodic Trends & Electron Configuration
Question 10 (3 marks)
Extended Response 1: Periodic Trends & Electron Configuration (b)
Explain why the second ionisation energy of Na is much greater than its first, but the increase from 1st to 2nd IE for Mg is less dramatic.
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Extended Response 1: Periodic Trends & Electron Configuration
Question 11 (3 marks)
Extended Response 1: Periodic Trends & Electron Configuration (c)
Arrange the following in order of increasing ionic radius and justify: NaβΊ, MgΒ²βΊ, AlΒ³βΊ, OΒ²β», Fβ».
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Extended Response 2: Bonding & Properties
Question 12 (4 marks)
Extended Response 2: Bonding & Properties (a)
Compare the melting points of NaCl (801Β°C), SiOβ (1710Β°C), Clβ (-101Β°C) and Na (98Β°C). Explain each in terms of bonding and structure.
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Extended Response 2: Bonding & Properties
Question 13 (3 marks)
Extended Response 2: Bonding & Properties (b)
Explain why COβ is a gas at room temperature but SiOβ is a solid, despite both being oxides of Group 14 elements.
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✓ Finished? Open the next lesson – Model Answers – to mark your work.